Craps Strategy: Place the 6 and 8 With a Field Bet

One interesting way to play craps is to combine Place bets on the 6 and 8 with a Field bet. The idea is to create frequent small wins while using the 6 and 8 to cover two of the most common dice totals.

For a simple example, let's use:

• $12 Place bet on 6
• $12 Place bet on 8
• $5 Field bet

That's $29 in action.

What Happens When a 6 or 8 Rolls?

A $12 Place bet on the 6 or 8 pays $14.

However, the Field loses when either number rolls.

So if a 6 rolls:

+$14 Place win − $5 Field loss = +$9

The same calculation applies to the 8:

+$14 Place win − $5 Field loss = +$9

This is the interesting part of the strategy. The Field and Place bets are working in opposite directions on a 6 or 8, but the Place payout is large enough to leave you with a $9 net profit.

What Happens When the Field Wins?

When a standard Field number rolls, the $5 Field bet generally pays $5.

Some casinos offer increased payouts on 2 or 12, making those rolls worth more.

So the basic winning pattern is easy to understand:

6 or 8 → +$9

Regular Field winner → +$5

Bonus-paying Field number → potentially +$10 or more

The 7 Is the Major Risk

The important number in this setup is the 7.

If a 7 rolls, the $12 Place 6, $12 Place 8 and $5 Field all lose.

That's:

−$12 − $12 − $5 = −$29

This creates the basic mathematical tradeoff of the strategy:

You are generally collecting $5 or $9 at a time, while a 7 can cost $29 at once.

A Simple Craps Math Example

Imagine this five-roll sequence:

4 → +$5

6 → +$9

9 → +$5

8 → +$9

7 → −$29

Now add everything together:

$5 + $9 + $5 + $9 = $28

Then the 7 arrives:

$28 − $29 = −$1

You had four winning rolls followed by one losing roll, yet you finished the sequence down $1.

That's the key mathematical point.

The strategy can produce a series of small wins, but those wins have to accumulate faster than the eventual larger loss.

How Many Small Wins Does It Take to Cover a 7?

This gives us another simple way to examine the strategy.

If you're winning $5 from regular Field hits, it takes almost six of those wins to cover one $29 loss:

6 × $5 = $30

If you're winning $9 from hits on the 6 or 8:

3 × $9 = $27

That's still not enough.

Four $9 wins would produce:

4 × $9 = $36

After a $29 loss:

$36 − $29 = +$7

So the important question isn't simply how often the strategy wins.

It's how much money has been accumulated before the 7 appears.

The Real Relationship Between the Field and the 6 and 8

The Field bet reduces the profit when the 6 or 8 rolls:

$14 becomes a $9 net win.

In return, the Field creates opportunities to collect $5 or more on many other rolls.

That makes the strategy a balancing act between frequency and size of wins.

The Place 6 and 8 provide the larger $9 net wins, while the Field provides smaller wins on its numbers.

The 7 represents the larger reset:

−$29

For players analyzing craps strategies, this is an important distinction. A betting system shouldn't be judged only by how frequently it produces a winning roll. The size of the wins compared with the size of the eventual loss is just as important.

Gus Santos